Hi Andreas,
Generally, the decorator uses an additional element to simulate the styling of the checkbox and replaces classes of the existing input element. This requires an additional workaround that relates to the TreeView and the checkBoxElement() method.
You can add the new workaround below the other one:
Regards,
Danail Vasilev
Telerik by Progress
Generally, the decorator uses an additional element to simulate the styling of the checkbox and replaces classes of the existing input element. This requires an additional workaround that relates to the TreeView and the checkBoxElement() method.
You can add the new workaround below the other one:
Telerik.Web.UI.RadTreeNode.prototype.get_checkBoxElement = function () { $ = $telerik.$; if (!this._checkBoxElement) this._checkBoxElement = $(this.get_contentElement()).find(".rfdRealInput, .rtChk, .rtChecked, .rtUnchecked, .rtIndeterminate").get(0) || null; return this._checkBoxElement;}Regards,
Danail Vasilev
Telerik by Progress
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